Breakthrough in the construction of nuclear fusion reactors - new calculations - a charged ionized Kawecki ring could replace the strongest electromagnets

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ITER magnet to be 13 T
Wendelstein 7-X magnets 6-15 T
MIT magnet 20 T
Chinese magnets 21.7 - 35.1 T
Tokamak Energy magnets 24.4 T

The velocity of a deuteron with kinetic energy of 1 MeV is approximately 9.79 × 10⁶ m/s


Maximum Lorentz magnetic force F = q × V × B

Deuteron charge 1.602176634×10^−19 C

The velocity of a deuteron with kinetic energy of 1 MeV is approximately 9.79 × 10⁶ m/s

Magnetic flux density also called magnetic B-field strength from 6 to 35.1 T
Checking the Lorentz magnetic force for 22 and 35 T

F 22 T = 1.602176634×10^−19 × 9.79 × 10^6 × 22 = 3.45076803 × 10^-11 newton N


F 35 T = 1.602176634×10^−19 × 9.79 × 10^6 × 35 = 5.48985824 × 10^-11 newton N


F 35.1 T = 1.602176634×10^−19 × 9.79 × 10^6 × 35.1 = 5.50554355 × 10^-11


Coulomb electric force F = q × E

Electric field intensity due to half the charged ionized ring E = 2 ÷ π × k × Q ÷ r^2 = 2 ÷ π × 1 ÷ ( 4 π × ε₀ ) × Q ÷ r^2

Q electric charge of half the charged ionized ring

Electric field intensity required to produce the equivalent magnetic force on a deuteron with a velocity of approximately 9.79 × 10⁶ m/s in a magnetic field of 35.1 tesla T
E = F ÷ q

F = 5.50554355 × 10^-11 newton N
q Charge of deuteron 1.602176634×10^−19 C

E = 5.50554355 × 10^-11 ÷ ( 1.602176634×10^−19 ) = 343,629,000.27164 N / C newton / coulomb

E = 2 ÷ π × 1 ÷ ( 4 π × ε₀ ) × Q ÷ r^2


Q = E × π ÷ 2 × 4 π × ε₀ × r^2 = E × π^2 × 2 × ε₀ × r^2

E = 343,629,000.27164 N / C

ε₀ = 8.854187812813 × 10^−12 F/m

Q = 343,629,000.27164 × π^2 × 2 × 8.854187812813 × 10^−12 × 0.16^2 = 343,629,000.27164 × π^2 × 2 × 8.8541878128 × 10^−12 × 0.16^2 = 0.0015374756 C


It's a bit low, I'll check later, but if there's no mistake, it's shockingly low

* edit Additional data check

According to the data validation analysis using ChatGPT and Copilot, the maximum confirmed real surface charge density σ = ~ 10^-3 C / m², i.e. 0.001 C/m², so if the limit is the surface charge density σ = ~ 0.001 C/m², it is enough to increase the surface area of ​​the metal elements or the metal part of the ring and it is possible to obtain the calculated charge Q = 0.0015374756 C - if the ring cannot be charged more by charging its elements on both sides, then with dimensions of 1 m circumference - radius of about 16 cm and a ring width of about 10 - 20 cm or even 30 cm, you can make a 6 - 7 - 10 - 20 layered ring, and if the area of ​​both sides is taken into account in double-sided charging, you can make fewer layers or reduce the dimensions and you can easily get an area of ​​2 m².

For comparison, I previously calculated that a mini piece of copper measuring 1 mm by 1 mm by 1 mm can be charged
Q = 13.5664942388 coulombs C
At an ionization voltage of
U = 33,928,277.445413 V

13.5664942388 C ÷ 0.0015374756 C = 13.5664942388 ÷ 0.0015374756 = 8,823.8761244731 times less charge, so we calculate how much we can reduce the ionization voltage and the dimensions of the copper piece to maintain a charge of 0.0015374756 C
cube root cbrt(8,823.8761244731) = 20.6642573027 times

U = 33,928,277.445413 V ÷ 20.6642573027 = 33,928,277.445413 ÷ 20.6642573027 = 1,641,882.2582595 volts V

So instead of using expensive, energy-intensive electromagnets with a magnetic flux density also called magnetic B-field strength of, for example, 35.1 Tesla T, simply use a charged ionized ring - a voltage of 1,641,882.2582595 volts V is enough.


For comparison, small pocket-sized stun guns available on the market can have a voltage of 50-98 million volts V, and a lightning bolt can have a voltage of 100 million to 1 billion volts V.

5 Liters of Copper × 8.935 kg/L = 44.675 kg
44.675 kg × 80 PLN/kg = 3,574 PLN + cost of ionizer, inverter and other accessories